The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that we can still apply Gauss's law to a Gaussian surface that is entirely within an insulator by replacing the right-hand side of Gauss's law, Qin/€0, with Qin /s, where & is the permittivity of the material. (Technically, & is called the vacuum permittivity.) Suppose that a 75 nC point charge is surrounded by a thin, 32-cm-diameter spherical rubber shell and that the electric field strength inside the rubber shell is 2500 N/C. Part A What is the permittivity of rubber? € = IVE ΑΣΦ xa Submit Xb 7 √x vx x x Previous Answers Request Answer IXI ? X.10n X C²/N-m²

The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that we can still apply Gauss's law to a Gaussian surface that is entirely within an insulator by replacing the right-hand side of Gauss's law, Qin/€0, with Qin /s, where & is the permittivity of the material. (Technically, & is called the vacuum permittivity.) Suppose that a 75 nC point charge is surrounded by a thin, 32-cm-diameter spherical rubber shell and that the electric field strength inside the rubber shell is 2500 N/C. Part A What is the permittivity of rubber? € = IVE ΑΣΦ xa Submit Xb 7 √x vx x x Previous Answers Request Answer IXI ? X.10n X C²/N-m²

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 68PQ: Examine the summary on page 780. Why are conductors and charged sources with linear symmetry,...

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