You have a convex, spherical mirror (as shown below) with a radius of curvature R=3.22m (the distance of the "Radial Line" shown in the image below). You shine light rays that are parallel to the principlal axis of the mirror as shown below that reflect in such a way that it appears all rays originated at the a point called the focal point of the mirror (F). Along the principal axis of the mirror, how far behind the mirror is the focal point (in meters)? It is important to point out that the focal point of convex mirrors, strictly speaking, is negative. This is because the object appears to originate from behind the mirror. Here, don't worry about the negative sign. Give a positive answer. Principal axis Radial line, normal to mirror surface Note: Do not explicitly include units in your answer (it is understood the unit is meter). Enter only a number. If you do enter a unit, your answer will be counted wrong.

You have a convex, spherical mirror (as shown below) with a radius of curvature R=3.22m (the distance of the "Radial Line" shown in the image below). You shine light rays that are parallel to the principlal axis of the mirror as shown below that reflect in such a way that it appears all rays originated at the a point called the focal point of the mirror (F). Along the principal axis of the mirror, how far behind the mirror is the focal point (in meters)? It is important to point out that the focal point of convex mirrors, strictly speaking, is negative. This is because the object appears to originate from behind the mirror. Here, don't worry about the negative sign. Give a positive answer. Principal axis Radial line, normal to mirror surface Note: Do not explicitly include units in your answer (it is understood the unit is meter). Enter only a number. If you do enter a unit, your answer will be counted wrong.

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter2: Geometric Optics And Image Formation

Section: Chapter Questions

Problem 13CQ: Use a ruler and a protractor to find the image by refraction in the following cases. Assume an...

See similar textbooks

Similar questions

Use a ruler and a protractor to find the image by refraction in the following cases. Assume an air-glass interface. Use a refractive index of 1 for air and of 1.5 for glass. (Hint: Use Snell’s law at the interface.) (a) A point object located on the axis of a concave interface located at a point within the focal length from the vertex. (b) A point object located on the axis of a concave interface located at a point farther than the focal length from the vertex. (c) A point object located on the axis of a convex interface located at a point within the focal length from the vertex. (d) A point object located on the axis of a convex interface located at a point farther than the focal length from the vertex. (e) Repeat (a)—(d) for a point object off the axis.
The end of a solid glass rod of refractive index 1.50 is polished to have the shape of a hemispherical surface of radius 1.0 cm. A small object is placed in air (refractive index 1.00) on the axis 5.0 cm to the left of the vertex. Determine the position of the image.
Suppose you have a concave mirror as shown in the image below. If h = 1.84m is the height of an object (really the displacement of the top of the object from the axis) and h′ = 4.21m is the height of the image, what is the magnitude of the transverse magnification (in units of meters)?
An optician directs a laser beam at right angles to the long face (or hypotenuse) of a 45°–45°–90° prism immersed in air, as shown in the figure below. The beam undergoes total internal reflection at each of the two sides making up the legs of the right triangle. For this to occur, what must be the minimum index of refraction for the material making up the prism?
A concave (converging) mirror is made out of a section of a spherical surface with radius = 3.35 m. If you look into this mirror with your face at a distances = 1.75 m from the mirror's vertex (center), what is the magnification of your face's image in the mirror (key in a negative sign if the value is negative)?
Consider a concave mirror with radius R. An upright object is placed between the interval R/2 and R The image is 1. virtual, inverted, enlarged. 2. virtual, inverted, reduced. 3. virtual, upright, same size. 4. real, upright, enlarged. 5. real, inverted, enlarged. 6. real, inverted, reduced. 7. real, upright, same size 8. virtual, upright, reduced. 9. virtual, upright, enlarged. 10. real, upright, reduced
A man stands in front of a vertical plane mirror, as shown in the figure. His eyes are 1.85 m above the floor and the top of his head is 0.15 m higher than that. Part (a) Find the height above the floor, in meters, of the bottom edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted hb in the figure. Part (b) Find the height above the floor, in meters, of the top edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted ht in the figure.
An object is placed in front of a concave spherical mirror as shown below. The three rays 1, 2 and 3, leave the top of the object and, after reflection, converge at a point on the top of the image. Ray 1 passes through C, ray 2 passes through F, and ray 3 is parallel to the principal axis. Which ray(s) will reflect back on itself (themselves)? A) both 1 and 2 B) 3 only C) 2 only D) 1 only E) both 1 and 3
A leaf of length h is positioned d = 65.9 cm in front of a converging lens with a focal length of 40.0 cm. An observer views the image of the leaf from a position 1.26 m behind the lens, as shown in the figure below. An eye on the right side of the figure looks left along a horizontal Principal axis that runs through the centers of a converging lens left of middle and a leaf on the left. The eye is a horizontal distance of 1.26 m from the lens, and the leaf is a horizontal distance d from the lens. (a) What is the magnitude of the lateral magnification (the ratio of image size to the object size) produced by the lens?(b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the leaf directly?
You are drawing a ray diagram for an object reflecting in a spherical mirror. You draw principal ray 1 and principal ray 2, and you find that they don't intersect. Which of the following is true? A. The image formed by this object is virtual. B. You will need to draw principal ray 3 to determine where the image is and what kind of image it is. C. You made a mistake drawing rays 1 and 2. D. The image formed by this object is inverted.
A man inside a spherical diving bell watches a fish through a window in the bell, as in the figure below. If the diving bell has radius R = 1.88 m and the fish is a distance p = 1.32 m from the window, calculate the image distance and the magnification. Neglect the thickness of the window. (Use 1.333 and 1.000 for the indices of refraction of water and air, respectively.) An illustration shows a person inside a submerged spherical diving bell of radius R. The person observes a fish shown to be a distance p beyond the diving bell's viewing window. (a) the image distance (in m) answer in m (b) the magnification
The diverging lens of the figure produces an image of an object to the left of the lens and 5.00 cm away from the center of the lens. The refracting index of the lens is 1.50. The magnitude of the focal length of the lens is 12.0 cm and the radius of curvature R1 is 15.0 cm. A.) Is the image formed by the lens upright or inverted compared to the object? (Select one.)