The electric field of the material between two coaxial cables of radius 0.525 cm and 0.675 cm is given as E = 2.85 V.m/r3. If the conductivity of the material is 5 x 1010 S/m, what is the current density in the material?

The electric field of the material between two coaxial cables of radius 0.525 cm and 0.675 cm is given as E = 2.85 V.m/r3. If the conductivity of the material is 5 x 1010 S/m, what is the current density in the material?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter21: Current And Direct Current Circuits

Section: Chapter Questions

Problem 17P

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

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The electric field of the material between two coaxial cables of radius 0.525 cm and 0.675 cm is given as E = 2.85 V.m/r³. If the conductivity of the material is 5 x 10¹⁰ S/m, what is the current density in the material?

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