. The electric field of the material between two coaxial cables of radius 0.525 cm and 0.675 cm is given as E= (2.85 V•m) / r3. If the conductivity of the material is 5 x 1010 S/m, what is the current density in the material?

. The electric field of the material between two coaxial cables of radius 0.525 cm and 0.675 cm is given as E= (2.85 V•m) / r3. If the conductivity of the material is 5 x 1010 S/m, what is the current density in the material?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter20: Electric Current, Resistance, And Ohm's Law

Section: Chapter Questions

Problem 13PE: A large cyclotron directs a beam of He ++ nuclei onto a target with a beam current of 0.250 mA. (a)...

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

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1. The electric field of the material between two coaxial cables of radius 0.525 cm and 0.675 cm is given as E= (2.85 V•m) / r³. If the conductivity of the material is 5 x 10¹⁰ S/m, what is the current density in the material?

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