The electric force between two horizontal charged parallel plates is F = -(4 x 10-6 )/y 2 N. Assume the lower plate is fixed at y = 0. Calculate the work you must do to move the upper plate from y = 1 mm to y = 2 mm (you are separating the plates when you do this). Note that the electric force is pointed down and so the force you apply is pointed up.
Dielectric Constant Of Water
Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.
Electrostatic Potential and Capacitance
An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
The electric force between two horizontal charged parallel plates is F = -(4 x 10-6 )/y 2 N. Assume the lower plate is fixed at y = 0. Calculate the work you must do to move the upper plate from y = 1 mm to y = 2 mm (you are separating the plates when you do this). Note that the electric force is pointed down and so the force you apply is pointed up.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
