The electric potential on the surface of a charged conducting sphere is 210 V, and 10.0 cm farther from the center of the sphere the potential is 140 V. (a) Determine the radius of the sphere. HINT: Use a ratio of the two given potentials to solve for the radius. 20 v cm (b) Determine the charge on the sphere. 4.67 v nC The electric potential on the surface of another charged conducting sphere is 240 V, and 10.0 cm farther from the center the magnitude of the electric field is 410 V/m (c) Determine all possible values for the radius of the sphere. (Enter your answers from smallest to largest. If only one value exists, enter "NONE" in the secor answer blank.) HINT: Use the ratio of the potential at the surface to the E field at the surface plus 10.0 cm to solve for the radii. cm r2 = cm (d) Determine the charge on the sphere for each value of r. (If only one value exists, enter "NONE" in the second answer blank.) 91 = nC 92 = nC

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
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Chapter7: Electric Potential
Section: Chapter Questions
Problem 60P: A metallic sphere of radius 2.0 cm is charged with +5.0C charge, which spreads on the surface of the...
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The electric potential on the surface of a charged conducting sphere is 210 V, and 10.0 cm farther from the center of the sphere the potential is 140 V.
(a) Determine the radius of the sphere. HINT: Use a ratio of the two given potentials to solve for the radius.
20
cm
(b) Determine the charge on the sphere.
4.67
nC
The electric potential on the surface of another charged conducting sphere is 240 V, and 10.0 cm farther from the center the magnitude of the electric field is 410 V/m.
(c) Determine all possible values for the radius of the sphere. (Enter your answers from smallest to largest. If only one value exists, enter "NONE" in the second
answer blank.) HINT: Use the ratio of the potential at the surface to the E field at the surface plus 10.0 cm to solve for the radii.
cm
r2 =
cm
(d) Determine the charge on the sphere for each value of r. (If only one value exists, enter "NONE" in the second answer blank.)
91 =
nC
92 =
Transcribed Image Text:The electric potential on the surface of a charged conducting sphere is 210 V, and 10.0 cm farther from the center of the sphere the potential is 140 V. (a) Determine the radius of the sphere. HINT: Use a ratio of the two given potentials to solve for the radius. 20 cm (b) Determine the charge on the sphere. 4.67 nC The electric potential on the surface of another charged conducting sphere is 240 V, and 10.0 cm farther from the center the magnitude of the electric field is 410 V/m. (c) Determine all possible values for the radius of the sphere. (Enter your answers from smallest to largest. If only one value exists, enter "NONE" in the second answer blank.) HINT: Use the ratio of the potential at the surface to the E field at the surface plus 10.0 cm to solve for the radii. cm r2 = cm (d) Determine the charge on the sphere for each value of r. (If only one value exists, enter "NONE" in the second answer blank.) 91 = nC 92 =
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