Please do. It correct I will rate ur solution but correct pls The ends of the 0.58-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.46 m/s and anacceleration of 0.37 m/s? in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative ifclockwise) of the bar and the acceleration of end A (positive if up, negative if down).290.58 m104°B=0.37mkUp =0.46 m/sAnswers:d =rad/s?m/s?

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The ends of the 0.58-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.46 m/s and an acceleration of 0.37 m/s2 in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down). 29 0.58 m 104° ag = 0.37 mk? Up =0.46 ms B Answers: rad/s? aA = m/s?

The ends of the 0.58-m bar remain in contact with their respective support surfaces. End B has a velocity of 0.46 m/s and an acceleration of 0.37 m/s2 in the directions shown. Determine the angular acceleration a (positive if counterclockwise, negative if clockwise) of the bar and the acceleration of end A (positive if up, negative if down). 29 0.58 m 104° ag = 0.37 mk? Up =0.46 ms B Answers: rad/s? aA = m/s?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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