Please explain it. The epuilibrium coms tant, kc, for thePollowing is 6.30 at R3K.reacfon6.30 at 7R3K.2NH.3(8(9)+3Hat3)If am eguilibrium mixtne of thethnee gasesat 723k confeais Oi479 Mole afma 14.3L containerFaroland O.347 Mole of No, the0.479MoleNitsl9)epuitionim Concen tration of Hois.M.

Kc is the ratio of product of concentration of products raised to their stoichiometric coefficient…

The epuilibium cons tont, kc, for the pOllowing reacfon is 6.30 at R3K. +3Hzt8) If am eguilinm mixtene of the Hyree gases at 728 k conftairs Oi479 mote of in a 14.3 L container and O. 347 mole of Na, the NHsla) epuilionim Concen tration of Ha M.

The epuilibium cons tont, kc, for the pOllowing reacfon is 6.30 at R3K. +3Hzt8) If am eguilinm mixtene of the Hyree gases at 728 k conftairs Oi479 mote of in a 14.3 L container and O. 347 mole of Na, the NHsla) epuilionim Concen tration of Ha M.

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 10CR

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

Please explain it.

The epuilibrium coms tant, kc, for the
Pollowing is 6.30 at R3K.
reacfon
6.30 at 7R3K.
2NH.
3(8
(9)
+3Hat3)
If am eguilibrium mixtne of the
thnee gases
at 723k confeais Oi479 Mole af
ma 14.3L container
Farol
and O.347 Mole of No, the
0.479Mole
Nitsl9)
epuitionim Concen tration of Ho
is.
M.

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