Answered: The equation of motion of a simple…

The equation of motion of a simple harmonic oscillator is given by x(t) = 0.4 cos (nt/2 + 1/4). At what time will the oscillator pass by the equilibrium position, x = 0, for the first time?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Oscillatory Motion

Section: Chapter Questions

Problem 2OQ

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Question

The equation of motion of a simple
harmonic oscillator is given by x(t) =
0.4 cos (nt/2 + 1/4). At what time will
the oscillator pass by the equilibrium
position, x = 0, for the first time?
O t = 2.5 sec
O t = 1.5 sec
Ot=4.5 sec
O t = 0.5 sec
O t = 3.5 sec

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