The equations re + uz – cos(v) - 2 = 0 and u cos(y) + 2x²v – 7yz2 –1= 0 can be solved for (u,v) as functions of (x.y,z) near the point P(xy,z,u,v)=(2,0,1,1,0). Find ()zy at (2,0,1). (re" + uz – cos(v) - 2=0 ve u cos(y) + 2a²v – 7yz? – 1= 0 denklemleri P(xy,z,u,v) = (2,0,1,1,0) noktası civarında (x,y,z)'nin fonksiyonu olmak üzere (u,v) için çözümlüdür. (2,0,1) noktasında ()z.y 'yi hesaplayınız.)

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