The equilibrium constant for the following reaction is 20.9 at 907 °C. 2 SO2(g) + O2(g) 2 SO3(g) K= 20.9 at 907 °C Calculate the equilibrium constant for the following reactions at 907 °C. (a) 2 SO3(g) 2 SO2(g) + O2(g) K = (b) SO3(g) SO (g) + 1/2 02(g) K =

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter12: Gaseous Chemical Equilibrium
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Problem 20QAP: Consider the following hypothetical reactions and their equilibrium constants at 75C,...
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The equilibrium constant for the following reaction is 20.9 at 907 °C.
2 SO2(g) + O2(g)
2 SO3(g)
K= 20.9 at 907 °C
Calculate the equilibrium constant for the following reactions at 907 °C.
(a) 2 SO3(g)
2 SO2(g) + 02(g)
K=
(b) SO3(g)
SO (g) + 1/2 O2(g)
K=
Transcribed Image Text:The equilibrium constant for the following reaction is 20.9 at 907 °C. 2 SO2(g) + O2(g) 2 SO3(g) K= 20.9 at 907 °C Calculate the equilibrium constant for the following reactions at 907 °C. (a) 2 SO3(g) 2 SO2(g) + 02(g) K= (b) SO3(g) SO (g) + 1/2 O2(g) K=
Expert Solution
Step 1) Equilibrium expression

* equilibrium constant (K) 

 K = [products]stiochiometric coefficient   /

       [Reactants]stiochiometric coefficient 

 

* For reaction =>

1)     2SO2(g) + O2(g)  = 2SO3(g) 

           K = 20.9

2)   2SO3(g) = 2SO2(g) + O2(g) 

           K = ? 

3)   SO3(g) = SO2(g) + 1/2 O2(g) 

           K = ? 

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