The equilibrium constant for the reaction 2 HF (g) = H2 (g) + F2 (g) is 0.140 at a particular temperature. What is the equilibrium constant for the equation 12 H2 (g) +2 F2 (g) = HF (g)?

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter14: Chemical Equilibrium
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Do the step by step solution and final solution
The equilibrium constant
for the reaction 2 HF (g) =
H2 (g) + F2 (g) is 0.140 at a
particular temperature.
What is the equilibrium
constant for the equation
12 H2 (g) +2 F2 (g) = HF
(g)?
Transcribed Image Text:The equilibrium constant for the reaction 2 HF (g) = H2 (g) + F2 (g) is 0.140 at a particular temperature. What is the equilibrium constant for the equation 12 H2 (g) +2 F2 (g) = HF (g)?
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