The equilibrium constant is 1.48 for the reaction below at 800.0 K. What would be the equilibrium constant with respect to pressure, Kp, at this temperature? 2 NO2 (g) rit 2 NO + O2 (g) (g)

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 49P
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The equilibrium constant is 1.48 for the reaction below at
800.0 K. What would be the equilibrium constant with
respect to pressure, Kp, at this temperature?
2 NO2 (g)
دام
2 NO (g)
+ O2 (g)
Transcribed Image Text:The equilibrium constant is 1.48 for the reaction below at 800.0 K. What would be the equilibrium constant with respect to pressure, Kp, at this temperature? 2 NO2 (g) دام 2 NO (g) + O2 (g)
Expert Solution
Step 1

Given reaction:-

 2 NO2(g) <==> 2NO(g) + O2(g)

Here,

∆n  = (Gaseous product)-(Gaseous reactant) 

∆n  =  (2+1) - (2)

∆n = 1

=> Given Kc = 1.48

Temperature (T) = 800 K

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