1 4.4.The equilibrium constant, K, for the following reaction is 7.00x10-5 at 673 K.NH4I(S) NH3(9) + HI(g)An equilibrium mixture of the solid and the two gases in a 1.00 L flask at 673 K conmol NH4I, 8.37x10-³ M NH3 and 8.37x10-³ M HI. If the concentration of HI(g)increased to 1.56x10-2 M, what will be the concentrations of the two gases once ebeen reestablished?[NH3] =[HI]The equilibrium constant, K, for the following reaction is 1.80x10-2 at 698 K.2HI(g) H₂(g) + 1₂ (9)?ΣΣAn equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.3054.09x10-² M H₂ and 4.09×10-2 M I₂. What will be the concentrations of the threeequilibrium has been reestablished, if 2.24x10-2 mol of I₂(g) is added to the flask?[HI] =[H₂] =[1₂] =ΣΣΣ

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The equilibrium constant, K, for the following reaction is 1.80x10-2 at 698 K. 2HI(g) H₂(g) + 1₂ (9) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.30 4.09×10-2 M H₂ and 4.09x10-2 M I₂. What will be the concentrations of the thre equilibrium has been reestablished, if 2.24x10-2 mol of I₂(g) is added to the flask [HI]=1 [H₂] = [1₂] M M M

The equilibrium constant, K, for the following reaction is 1.80x10-2 at 698 K. 2HI(g) H₂(g) + 1₂ (9) An equilibrium mixture of the three gases in a 1.00 L flask at 698 K contains 0.30 4.09×10-2 M H₂ and 4.09x10-2 M I₂. What will be the concentrations of the thre equilibrium has been reestablished, if 2.24x10-2 mol of I₂(g) is added to the flask [HI]=1 [H₂] = [1₂] M M M

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.35PAE: In the reaction in Exercise 12.33, another trial was carried out. The reaction began with an initial...

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