The equilibrium constant, Kc, for the following reaction Is 10.5 at 350. K. 2CH2Cl2 (g) = CH4(g) + CCl4 (g) Calculate the equilibrium concentrations of reactant and products when 0.205 moles of CH2Cl2 (g) are introduced into a 1.00 L vessel at 350. K. [CH2C12] =____M [CH4] =____M [CCl4]=____M The equilibrium constant, Kc, for the following reaction is 1.29×10^2 at 600 K. COCl2(g)= CO(g) + Cl2(g) Calculate the equilibrium concentrations of reactant and products when 0.274 moles of COCl2(g) are introduced into a 1.00 L vessel at 600 K. [COCl2]=____M [CO]=____ M [Cl2]=____M

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 38GQ: At 2300 K the equilibrium constant for the formation of NO(g) is 1.7 103. N2(g) + O2(g) 2 NO(g)...
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The equilibrium constant, Kc, for the following reaction Is 10.5 at 350. K. 2CH2Cl2 (g) = CH4(g) + CCl4 (g) Calculate the equilibrium concentrations of reactant and products when 0.205 moles of CH2Cl2 (g) are introduced into a 1.00 L vessel at 350. K. [CH2C12] =____M [CH4] =____M [CCl4]=____M The equilibrium constant, Kc, for the following reaction is 1.29×10^2 at 600 K. COCl2(g)= CO(g) + Cl2(g) Calculate the equilibrium concentrations of reactant and products when 0.274 moles of COCl2(g) are introduced into a 1.00 L vessel at 600 K. [COCl2]=____M [CO]=____ M [Cl2]=____M
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