The equilibrium constant Kc for the gaseous reaction HCHO(g) ⇀↽ H2(g) + CO(g) has the numerical value 0.50 at 600◦C. A mixture of HCHO, H2, and CO is introduced into a flask at 600◦C. After a short time, analysis of a small sample of the reaction mixture shows the concentrations to be [HCHO] = 1.5 mol/L, [H2] = 0.5 mol/L and [CO] = 1.0 mol/L. Which of the following statements about this reaction is true?The reaction mixture is not at equilibrium, but no further reaction will occur. The reaction mixture is not at equilibrium, but will move toward equilibrium by forming more HCHO. The reaction mixture is at equilibrium. The forward rate of this reaction is the same as the reverse rate at those concentrations. The reaction mixture is not at equilibrium, but will move toward equilibrium by using up more HCHO.

Equilibrium point is the point where rate of forward reaction is equal to the rate of backward…

Answered: The equilibrium constant Kc for the…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 60QRT

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The equilibrium constant Kc for the gaseous reaction HCHO(g) ⇀↽ H2(g) + CO(g) has the numerical value 0.50 at 600◦C. A mixture of HCHO, H2, and CO is introduced into a flask at 600◦C. After a short time, analysis of a small sample of the reaction mixture shows the concentrations to be [HCHO] = 1.5 mol/L, [H2] = 0.5 mol/L and [CO] = 1.0 mol/L. Which of the following statements about this reaction is true?

The reaction mixture is not at equilibrium, but no further reaction will occur.
The reaction mixture is not at equilibrium, but will move toward equilibrium by forming more HCHO.
The reaction mixture is at equilibrium.
The forward rate of this reaction is the same as the reverse rate at those concentrations.
The reaction mixture is not at equilibrium, but will move toward equilibrium by using up more HCHO.

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