The equilibrium constant, Ko, for the following reaction is 1.80x10-2 at 698 K. 2HI(g) H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and products when 0.256 moles of HI are introduced into a 1.00 L vessel at 698 K. [HI] = M [H2] =| [12] = M M

Chemistry: The Molecular Science
5th Edition
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Author:John W. Moore, Conrad L. Stanitski
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Chapter12: Chemical Equilibrium
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Problem 56QRT
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The equilibrium constant, Ke, for the following reaction is 1.80×10 2 at 698 K.
2HI(g) H2(g) + I2(g)
Calculate the equilibrium concentrations of reactant and products when 0.256 moles of HI are introduced into a 1.00 L vessel at 698 K.
[HI] =
M
[H2] =
[12] =
M
M
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Transcribed Image Text:The equilibrium constant, Ke, for the following reaction is 1.80×10 2 at 698 K. 2HI(g) H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and products when 0.256 moles of HI are introduced into a 1.00 L vessel at 698 K. [HI] = M [H2] = [12] = M M Submit Answer Retry Entire Group No more group attempts remain
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