The equilibrium equation of force in horizontal direction is, Та cos 30°- Tв сos 45° (IV) TA = 0.81657; • Ta is the tension in cord A • Tg is the tension in cord B The equilibrium equation of force in vertical direction is, TA sin 30° + Tc = TB sin 45° (V) Ta is the tension in cord A • TB is the tension in cord B • Tc is the tension in cord C The equilibrium equation of force for suspended object is, Tc = w (VI) • Tc is the tension in cord C • w is weight of suspended object Conclusion: Substitute 0.8165TB for TA and w for Te in eqs. (V) to find Tg. (0.8165TB) sin 30° + w = Tg sin 45° 0.299TB = w Тв — 3.346w Substitute 3.346w for Tg in eqs. (IV) to find TĄ. TA = 0.8165 x (3.346w) TA = 2.732w Therefore tension in cord A is 2.732w. Tension in cord B is 3.346w. Tension in cord C is w.
The equilibrium equation of force in horizontal direction is, Та cos 30°- Tв сos 45° (IV) TA = 0.81657; • Ta is the tension in cord A • Tg is the tension in cord B The equilibrium equation of force in vertical direction is, TA sin 30° + Tc = TB sin 45° (V) Ta is the tension in cord A • TB is the tension in cord B • Tc is the tension in cord C The equilibrium equation of force for suspended object is, Tc = w (VI) • Tc is the tension in cord C • w is weight of suspended object Conclusion: Substitute 0.8165TB for TA and w for Te in eqs. (V) to find Tg. (0.8165TB) sin 30° + w = Tg sin 45° 0.299TB = w Тв — 3.346w Substitute 3.346w for Tg in eqs. (IV) to find TĄ. TA = 0.8165 x (3.346w) TA = 2.732w Therefore tension in cord A is 2.732w. Tension in cord B is 3.346w. Tension in cord C is w.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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How did it resulted to 0.346? Isn't it supposed to be 3.3444?
Transcribed Image Text:The equilibrium equation of force in horizontal direction is,
Та cos 30°- Tв сos 45°
(IV)
TA = 0.81657;
• Ta is the tension in cord A
• Tg is the tension in cord B
The equilibrium equation of force in vertical direction is,
TA sin 30° + Tc = TB sin 45° (V)
Ta is the tension in cord A
• TB is the tension in cord B
• Tc is the tension in cord C
The equilibrium equation of force for suspended object is,
Tc = w (VI)
• Tc is the tension in cord C
• w is weight of suspended object
Conclusion:
Substitute 0.8165TB for TA and w for Te in eqs. (V) to find Tg.
(0.8165TB) sin 30° + w = Tg sin 45°
0.299TB = w
Тв — 3.346w
Substitute 3.346w for Tg in eqs. (IV) to find TĄ.
TA = 0.8165 x (3.346w)
TA = 2.732w
Therefore tension in cord A is 2.732w. Tension in cord B is 3.346w. Tension
in cord C is w.
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