A block of mass m 2.00 kg is sitting stationary on a table. A horizontal force of magnitude F = 5.00 N is applied to the block, as shown. The coefficient of static friction is us = 0.700, and the coefficient of kinetic friction is HK = 0.500. What is the %3D magnitude of the force of friction between the block and the table, in units of newtons? Enter the numerical answer without units. Your answer must be within 1% of the exact answer to receive credit. Hs = 0.7 m = HK = 0.5 2.0 kg F = 5.0 N block at rest vered Answers

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Chapter1: Units, Trigonometry. And Vectors
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Why is 5 the correct answer ?

A block of mass m 2.00 kg is sitting stationary on a table. A horizontal force of
magnitude F = 5.00 N is applied to the block, as shown. The coefficient of static
friction is us = 0.700, and the coefficient of kinetic friction is HK = 0.500. What is the
%3D
magnitude of the force of friction between the block and the table, in units of
newtons? Enter the numerical answer without units. Your answer must be within 1% of
the exact answer to receive credit.
Hs = 0.7
m =
HK = 0.5
2.0 kg
F = 5.0 N
block at rest
vered
Answers
Transcribed Image Text:A block of mass m 2.00 kg is sitting stationary on a table. A horizontal force of magnitude F = 5.00 N is applied to the block, as shown. The coefficient of static friction is us = 0.700, and the coefficient of kinetic friction is HK = 0.500. What is the %3D magnitude of the force of friction between the block and the table, in units of newtons? Enter the numerical answer without units. Your answer must be within 1% of the exact answer to receive credit. Hs = 0.7 m = HK = 0.5 2.0 kg F = 5.0 N block at rest vered Answers
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