The equilibrium for the precipitation of CaCO3 from its ions in solution is 2.2 x 10*8Ca+2(aq) + CO3 (aq) <--> CaCO3(s).Whatthe equilibrium constant for the reverse of this equation, where CaCO3dissolves in water to form ions?Oa. 22 x 10-8Ob.4.5 x 10+9Oc.C. 2.2 x 10-8Od. 45x 1092.2 x 10-8

The reaction given is, => Ca2+ (aq) + CO32- (aq) -------> CaCO3 (s)…

The equilibrium for the precipitation of CaCO3 from its ions in solution is 2.2 x 10*8. Ca+2 (aq) + CO3 (ag) <--> CACO3(s). What is the equilibrium constant for the reverse of this equation, where CaCO3 dissolves in water to form ions? Oa. 2.2 x 10-8 Ob. 4.5 x 10+9 Oc. C. 2.2 x 10-8 Od. 4.5 x 10-9

The equilibrium for the precipitation of CaCO3 from its ions in solution is 2.2 x 10*8. Ca+2 (aq) + CO3 (ag) <--> CACO3(s). What is the equilibrium constant for the reverse of this equation, where CaCO3 dissolves in water to form ions? Oa. 2.2 x 10-8 Ob. 4.5 x 10+9 Oc. C. 2.2 x 10-8 Od. 4.5 x 10-9

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter20: Chemistry Of The Metals

Section: Chapter Questions

Problem 34QAP: The equilibrium constant for the reaction 2CrO42(aq)+2H+(aq)Cr2O72(aq)+H2O is 31014 . What must the...

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Question

The equilibrium for the precipitation of CaCO3 from its ions in solution is 2.2 x 10*8
Ca+2
(aq) + CO3 (aq) <--> CaCO3(s).
What
the equilibrium constant for the reverse of this equation, where CaCO3
dissolves in water to form ions?
Oa. 22 x 10-8
Ob.
4.5 x 10+9
Oc.
C. 2.2 x 10-8
Od. 45x 109
2.2 x 10-8

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