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The experimental data for the reaction below is given: HBRO3 + 5HB 3B12 + 3 H2O [HBRO3] [HBr] Initial Trial (M) (M) Rate (MIs) 1 0.10 0.10 8.0 x 104 0.20 0.10 1.6 x 10-3 0.20 0.20 3.2 x 10-3 0.10 0.10 3.2 x 10-3 2. 3. 4.

The experimental data for the reaction below is given: HBRO3 + 5HB 3B12 + 3 H2O [HBRO3] [HBr] Initial Trial (M) (M) Rate (MIs) 1 0.10 0.10 8.0 x 104 0.20 0.10 1.6 x 10-3 0.20 0.20 3.2 x 10-3 0.10 0.10 3.2 x 10-3 2. 3. 4.

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 34E: Use the data provided in a graphical method to determine the order and rate constant of the...
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The experimental data for the reaction below is given: HBRO3 + 5HBR 3Br2 + 3 H2O [HBRO3] [HBr] (M) Initial Rate Trial (M/s) 0.10 0.10 8.0 x 104 0.20 0.10 1.6 x 10-3 3 0.20 0.20 3.2 x 10-3 0.10 0.10 3.2x10-3 2. 4.
Transcribed Image Text:The experimental data for the reaction below is given: HBRO3 + 5HBR 3Br2 + 3 H2O [HBRO3] [HBr] (M) Initial Rate Trial (M/s) 0.10 0.10 8.0 x 104 0.20 0.10 1.6 x 10-3 3 0.20 0.20 3.2 x 10-3 0.10 0.10 3.2x10-3 2. 4.
Use the data to calculate the specific rate constant K and overall order of the reaction. O K= 0.080 M-1s-1, overall order = 2nd O K= 0.77 M-1s-1, overall order = 2nd O K= 0.080 M-1s1, overall order = 1St OK= 0.77 M-1s-1, overall order = 3rd
Transcribed Image Text:Use the data to calculate the specific rate constant K and overall order of the reaction. O K= 0.080 M-1s-1, overall order = 2nd O K= 0.77 M-1s-1, overall order = 2nd O K= 0.080 M-1s1, overall order = 1St OK= 0.77 M-1s-1, overall order = 3rd
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