The factors of the constant term were divided by 3 instead of 1; The possible rational zeros of f are ±1, ±2, ±4, ± 8. The factors were listed as instead of ; The possible rational zeros of f are ±1, +, ±2, ±, ±4, ±, ±8, 3' There should only be positive zeros because the constant term is positive; The possible rational zeros of j are 1, 3, 7 2 78 1 1 3 There should only be fractions because rational zeros must be fractions; The possible rational zeros of f are + +, + =
The factors of the constant term were divided by 3 instead of 1; The possible rational zeros of f are ±1, ±2, ±4, ± 8. The factors were listed as instead of ; The possible rational zeros of f are ±1, +, ±2, ±, ±4, ±, ±8, 3' There should only be positive zeros because the constant term is positive; The possible rational zeros of j are 1, 3, 7 2 78 1 1 3 There should only be fractions because rational zeros must be fractions; The possible rational zeros of f are + +, + =
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.CR: Chapter Review
Problem 78E
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Question
This equation is about solving polynomial equations. In which describe and correct the error in listing the possible rationale zeros of the function. Photo shown below
Expert Solution
Step 1
NOTE: Refresh your page if you can't see any equations.
.
to find the zeros, take f(x)=0
here leading coefficient is
and the constant term is
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