The figure below is a stress strain curve for an alloy of aluminum at various temperatures. a) What is the yield stress at room temperature? b) Assume a rod made of this material is 20 cm long and at room temperature. If the rod were put in tension, how long would it be when it breaks? c) If the rod has cross-sectional area 1 cm², what force is required to break it (in tension)? Longitudinal RT 60 250F 350F 3아- 500F 20 0008 Strain, in/in. a.002 0.004 0.006 Q010 O012 A-3 Stress, ksi

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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The figure below is a stress strain curve for an alloy of aluminum at various temperatures.
a) What is the yield stress at room temperature?
b) Assume a rod made of this material is 20 cm long and at room temperature. If the
rod were put in tension, how long would it be when it breaks?
c) If the rod has cross-sectional area 1 cm?, what force is required to break it (in
tension)?
Longitudinal
RT
250F
350F
30
500F
0.002
0.004
0.006
0008
QO10
O012
Strain, in/in.
A-93
Stress, ksi
Transcribed Image Text:The figure below is a stress strain curve for an alloy of aluminum at various temperatures. a) What is the yield stress at room temperature? b) Assume a rod made of this material is 20 cm long and at room temperature. If the rod were put in tension, how long would it be when it breaks? c) If the rod has cross-sectional area 1 cm?, what force is required to break it (in tension)? Longitudinal RT 250F 350F 30 500F 0.002 0.004 0.006 0008 QO10 O012 Strain, in/in. A-93 Stress, ksi
Expert Solution
Step 1

(a)

Draw the line at the Centre between the temperatures 250k and 350k. This line gives line of 298k and the room temperature=298.15K.

Plot a graph at 298.15K we get curve at the middle of lines at 250k and 350k.

It have yeild stress at 45 ksi.

(b)

From the graph,

The breaking stress at room temperature is 50ksi.

Write the expression for the stress.

Stress =density*length*g

Length when breaks = 50/(9.8×density)

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