The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle.Constant pressureheat addition34PV = constant%3DHeatINAdiabaticexpansion2Heat OUT(Constant volumeheat rejection)Constantvolume heataddition1AdiabaticcompressionVolume (V)Using the Dual Air Standard Cycle and the following data:• Assume constant properties of air. R= 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4• Cycle compression ratio = 14 (V1/v2)• Air conditions prior to compression: Pressure = 1.3 bar; Temperature = 293K• Heat added at constant volume = 280000 J/kg• Heat added at constant pressure = 662000 J/kgPressure (P) a)Calculate the pressure at the end of the compression process.P2 =barb)Calculate the temperature at the end of the compression process.T2 =Kc)Calculate the temperature at the end of the constant volume heat addition process.T3 =K

(a) To find: The pressure at at the end of compression process. Given: The gas constant is R=287…

The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 4 PV = Pressure (P) Heat IN = constant Adiabatic expansion 2 5 Heat OUT (Constant volume heat rejection) Constant volume heat addition 1 Adiabatic compression Volume (V) Using the Dual Air Standard Cycle and the following data: • Assume constant properties of air. R = 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4 • Cycle compression ratio = 14 (V₁/V₂) • Air conditions prior to compression: Pressure = 1.3 bar; Temperature = 293K • Heat added at constant volume = 280000 J/kg • Heat added at constant pressure = 662000 J/kg

The figure below is the basic plot of pressure vs. volume for the Dual Standard Cycle. Constant pressure heat addition 3 4 PV = Pressure (P) Heat IN = constant Adiabatic expansion 2 5 Heat OUT (Constant volume heat rejection) Constant volume heat addition 1 Adiabatic compression Volume (V) Using the Dual Air Standard Cycle and the following data: • Assume constant properties of air. R = 287 J/kgK; Cp = 1005 J/kgK; Cv = 718 J/kgK; y = 1.4 • Cycle compression ratio = 14 (V₁/V₂) • Air conditions prior to compression: Pressure = 1.3 bar; Temperature = 293K • Heat added at constant volume = 280000 J/kg • Heat added at constant pressure = 662000 J/kg

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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