I JUST NEED RBULB2THE ONE MARKED WRONG The figure below shows three lightbulbs connected to a 120-V AC (rms) household supply voltage. Bulbs 1 and 2 have a power rating of 45 W, and bulb 3 has a 75-W rating.120 V(a) Find the rms current in each bulb.Ibulb.375A%D1I ulb.375A2Ibulb.625A(b) Find the resistance of each bulb.Rpulb 1= 320Ω= 192Rpulb 2Your response differs from the correct answer by more than 10%. Double check your calculations. 2Rpulb 3192%3D(c) What is the total resistance of the combination of the three lightbulbs?87.27Ω

Solution for wrong part b i.e., the value of R bulb 2 - Given that : Applied…

The figure below shows three lightbulbs connected to a 120-V AC (rms) household supply voltage. Bulbs 1 and 2 have a power rating of 45 W, and bulb 3 has a 75-W rating. 120 V 1 (a) Find the rms current in each bulb. bulb 1 =.375 bulb 2 =.375 Ibulb 3 =.625 A (b) Find the resistance of each bulb. Rbulb 1 = 320 = 192 Rpulb 2 Your response differs from the correct answer by more than 10%. Double check your calculations. N Rpulb 3 = 192 (c) What is the total resistance of the combination of the three lightbulbs? 87.27

The figure below shows three lightbulbs connected to a 120-V AC (rms) household supply voltage. Bulbs 1 and 2 have a power rating of 45 W, and bulb 3 has a 75-W rating. 120 V 1 (a) Find the rms current in each bulb. bulb 1 =.375 bulb 2 =.375 Ibulb 3 =.625 A (b) Find the resistance of each bulb. Rbulb 1 = 320 = 192 Rpulb 2 Your response differs from the correct answer by more than 10%. Double check your calculations. N Rpulb 3 = 192 (c) What is the total resistance of the combination of the three lightbulbs? 87.27

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter25: Electromagnetic Induction

Section25.1: Electric Current From Changing Magnetic Fields

Problem 6PP

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