The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage with L1 = 3 ft, L2 = 0.5 ft, and L3 = 1.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in Ib/ft³. Let g = 32 ft/s?. Pressure gage Air Oil (p = 55 bvit) Mercury (p 845 Ibn') - 32.2 fs Determine the reading of the pressure gage, in Ibf/in.? (gage).

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage,
with L1 = 3 ft, L2 = 0.5 ft, and L3 = 1.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in Ib/ft?. Let g = 32.2
ft/s?.
Pressure
gage
Air
Oil (p = 55 Ivit)
Pam
Mercury (p= 845 Ih/n')
g= 322 fus?
Determine the reading of the pressure gage, in Ibf/in.? (gage).
Pgage = i
Ibf/in.2
Transcribed Image Text:The figure belows shows a closed tank holding air and oil to which is connected a U-tube mercury manometer and a pressure gage, with L1 = 3 ft, L2 = 0.5 ft, and L3 = 1.75 ft. The densities of the oil and mercury are 55 and 845, respectively, each in Ib/ft?. Let g = 32.2 ft/s?. Pressure gage Air Oil (p = 55 Ivit) Pam Mercury (p= 845 Ih/n') g= 322 fus? Determine the reading of the pressure gage, in Ibf/in.? (gage). Pgage = i Ibf/in.2
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