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The figure is the vertical side of a form for poured concrete that weighs 140.7 pounds per cubic foot. Determine the force on this part of the concrete form. (Round your answer to one decimal place.) Semiellipse, y=- //v 36x2 lb 5 ft -6 ft

The figure is the vertical side of a form for poured concrete that weighs 140.7 pounds per cubic foot. Determine the force on this part of the concrete form. (Round your answer to one decimal place.) Semiellipse, y=- //v 36x2 lb 5 ft -6 ft

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.3: Vectors
Problem 73E
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The figure is the vertical side of a form for poured concrete that weighs 140.7 pounds per cubic foot. Determine the force on this part of the concrete form. (Round your answer to one decimal place.) 5 Semiellipse, y = - lb -x² 36 - 5 ft -6 ft
Transcribed Image Text:The figure is the vertical side of a form for poured concrete that weighs 140.7 pounds per cubic foot. Determine the force on this part of the concrete form. (Round your answer to one decimal place.) 5 Semiellipse, y = - lb -x² 36 - 5 ft -6 ft
A cylindrical gasoline tank is placed so that the axis of the cylinder is horizontal. Find the fluid force on a circular end of the tank when the tank is half full, where the diameter is 3 feet and the gasoline weighs 42 pounds per cubic foot. Step 1 A cylindrical gasoline tank is placed so that the axis of the cylinder is horizontal. Observe the following figure carefully. You get h(y) = y -2 -1 X I y 2 -1 2 1 2 X where h(y) is the depth of the tank from the x-axis.
Transcribed Image Text:A cylindrical gasoline tank is placed so that the axis of the cylinder is horizontal. Find the fluid force on a circular end of the tank when the tank is half full, where the diameter is 3 feet and the gasoline weighs 42 pounds per cubic foot. Step 1 A cylindrical gasoline tank is placed so that the axis of the cylinder is horizontal. Observe the following figure carefully. You get h(y) = y -2 -1 X I y 2 -1 2 1 2 X where h(y) is the depth of the tank from the x-axis.
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