The figure to the right gives the schematic of an air conditioner cycle that steadily circulates R134a through the four components shown. The R134a flows through the evaporator and condenser at constant pressure and through the compressor adiabatically and isentropically. Kinetic and potential energy effects can be ignored. Assume mass flow rate is 0.5 kg/s. Process data is as follows.

Refrigeration and Air Conditioning Technology (MindTap Course List)
8th Edition
ISBN:9781305578296
Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Chapter22: Condensers
Section: Chapter Questions
Problem 7RQ: When a standard-efficiency air-cooled condenser is used, the condensing refrigerant will normally be...
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PROBLEM 4:
The figure to the right gives the
schematic of an air conditioner cycle that
steadily circulates R134a through the four
components shown. The R134a flows
through the evaporator and condenser at
constant pressure and through the
compressor adiabatically and
isentropically. Kinetic and potential
energy effects can be ignored. Assume
mass flow rate is 0.5 kg/s. Process data is
as follows.
4.
Evaporator
in House
Throttling
Compressor
Value
Condenser
Outside
2.
Process 4-1: constant-pressure at 340 kPa from saturated liquid to saturated vapor.
Process 3-2: constant-pressure at 1000 kPa.
Process 3-4: constant enthalpy and We = 0
Part a.) Determine if cycle is internally reversible, irreversible, or impossible. If
impossible explain which of the assumptions above is probably incorrect.
Part b.) Determine the coefficient of performance.
Part c.) Fill in the tables below (except T3 and s3). USE THE UNITS GIVEN ON THE
TABLES!
T(C)
h(kl/kg)
s(k//kg*K)
State
P (kPa)
2
3.
4.
W (kW)
Change in Energy (kW)
Process
Q (kW)
1-2
2-3
3-4
4-1
ТОTAL
Transcribed Image Text:PROBLEM 4: The figure to the right gives the schematic of an air conditioner cycle that steadily circulates R134a through the four components shown. The R134a flows through the evaporator and condenser at constant pressure and through the compressor adiabatically and isentropically. Kinetic and potential energy effects can be ignored. Assume mass flow rate is 0.5 kg/s. Process data is as follows. 4. Evaporator in House Throttling Compressor Value Condenser Outside 2. Process 4-1: constant-pressure at 340 kPa from saturated liquid to saturated vapor. Process 3-2: constant-pressure at 1000 kPa. Process 3-4: constant enthalpy and We = 0 Part a.) Determine if cycle is internally reversible, irreversible, or impossible. If impossible explain which of the assumptions above is probably incorrect. Part b.) Determine the coefficient of performance. Part c.) Fill in the tables below (except T3 and s3). USE THE UNITS GIVEN ON THE TABLES! T(C) h(kl/kg) s(k//kg*K) State P (kPa) 2 3. 4. W (kW) Change in Energy (kW) Process Q (kW) 1-2 2-3 3-4 4-1 ТОTAL
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