The first-order rate constant for the decomposition of N205, given below, at 70°C is 6.82 10-3 s-4. Suppose we start with 0.0200 mol of N205(g) in a volume of 5.0 L. 2 N205(g) → 4 NO2(g) + O2(g) (a) How many moles of N205 will remain after 1.5 min? mol (b) How many minutes will it take for the quantity of N205 to drop to 0.005 mol? min (c) What is the half-life of N205 at 70°C? min

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Q: The first-order rate constant for the decomposition of N2O5, given below, at 70°C is 6.82 x 10-3…

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Q: Dinitrogen Pentoxide, N2O5, decomposes when heated to give in carbon tetrachloride solvent.…

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Q: The decomposition of N2O5 in solution in carbon tetrachloride is a first-order reaction. 2N2O5 →…

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A: 2 N2O5( soln) → 4 NO2( soln) + O2( soln) First order Reaction rate constant(K) = 4.82 × 10 -3 s-1…

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Q: 1. The first order rate constant for the decomposition of N205, according to the reaction: 2 N2O5(g)…

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Q: 1. The first order rate constant for the decomposition of N205, according to the reaction: 2 N2O5(g)…

A: Reaction given2N2O5 (g)→ 4 NO2(g) + O2(g)k = 6.82 ×10-3 s-1N2O50 =  0.0250 moles / 2 L = 0.0125 M

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