The flexible band F is attached at E to the rotating sector and leads over the guide pulley G. Determine the angular velocities of linksAB and BD for the position shown if the band has a speed of 2.0 m/s. The angular velocities are positive if counterclockwise, negativeif clockwise.OD2.0 m/s0.16 m11o0.24 m0.320.34 mAEAnswers:rad/sWABrad/sWBDII

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Asked Jul 7, 2019
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The flexible band F is attached at E to the rotating sector and leads over the guide pulley G. Determine the angular velocities of links
AB and BD for the position shown if the band has a speed of 2.0 m/s. The angular velocities are positive if counterclockwise, negative
if clockwise.
OD
2.0 m/s
0.16 m
11o
0.24 m
0.32
0.34 m
A
E
Answers:
rad/s
WAB
rad/s
WBD
II
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The flexible band F is attached at E to the rotating sector and leads over the guide pulley G. Determine the angular velocities of links AB and BD for the position shown if the band has a speed of 2.0 m/s. The angular velocities are positive if counterclockwise, negative if clockwise. OD 2.0 m/s 0.16 m 11o 0.24 m 0.32 0.34 m A E Answers: rad/s WAB rad/s WBD II

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Expert Answer

Step 1

Draw the schematic diagram of the link BA as shown in figure (1).

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(ICR) at oo C VB (ICR) at oo VA 0.34 m Figure 1 Calculate the velocity of link OA OA OE 0.24 -x 2 m/s 0.32 =1.5 m/s

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Step 2

Refer the figure (1),

The link AB has the instantaneous center at infinity so the velocity of the link OA is equal to velocity of point B.

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Similarly The link AB has the instantaneous center at infinity so the velocity of the link AB is equal to zero Mathematically expressed as 1.5 =0 Thus, the angular velocity of the link AB for the position shown is 0 rad/s

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Step 3

Consider the vertical link DB and ca...

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VB BD 1.5m/s 0.16 9.375 rad/s (CCw) Thus, the angular velocity of the link BD is 9.375 rad/s (CCW)

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