The following data were collected for the preparation of the Copper (i) chloride      in the lab. Atomic masses : Cu = 63.5, Cl = 35.5, H=  1.00 ,N = 14.00, Na = 23.0 ,       C = 12.0 g/mol, respectively i.   Weight of copper                            1.150 g ii  Volume of 15.8M nitric acid added                                              5.80 mL Iii  Weight of Na2CO3 added                                                           4.420  g iv  Experimental yield of CuCl obtained                                         2.970 g v   Theoretical yield of CuCl                                                                    ? vi   Percent yield of CuCl                                                                         ?     The following reactions should be useful: Cu(s) + 4HNO3((aq) →  Cu(NO3)2 + 2NO2(g) + H2O(l) ii   2HNO3(aq) + Na2CO3(s)         →  H2O(l) + CO2(g) + 2NaNO3(aq) iii. Cu(NO3)2(aq) + Na2CO3(s)      →  CuCO3(s) + 2NaNO3(aq) iv.  CuCO3(s) + 2HCl(aq) → CuCl2(aq) + H2O(l) + CO2(g) v.   CuCl2(aq) +Cu(s) →  2CuCl(s) Based on the above data, calculate the number of moles of HNO3 that are in   excess. Also based on the above data , the excess moles of HNO3 used,  and the    moles of  Cu(NO3)2 produced in the first step, how many grams of sodium  carbonate was   added     in excess.   The answer choices are given in this format.   HNO3(excess mols) Na2CO3(excess grams)           Group of answer choices 0.0152 4.420 0.0196 1.473 0.0724 2.623 0.0276 1.764

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter2: Chemical Compounds
Section: Chapter Questions
Problem 124QRT
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The following data were collected for the preparation of the Copper (i) chloride

     in the lab. Atomic masses : Cu = 63.5, Cl = 35.5, H=  1.00 ,N = 14.00, Na = 23.0 ,

      C = 12.0 g/mol, respectively

i.   Weight of copper

                           1.150 g

ii  Volume of 15.8M nitric acid added                  

                           5.80 mL

Iii  Weight of Na2CO3 added                               

                           4.420  g

iv  Experimental yield of CuCl obtained             

                           2.970 g

v   Theoretical yield of CuCl                                  

                                 ?

vi   Percent yield of CuCl                                       

                                 ?

 

 

The following reactions should be useful:

  1. Cu(s) + 4HNO3((aq) →  Cu(NO3)2 + 2NO2(g) + H2O(l)

ii   2HNO3(aq) + Na2CO3(s)         →  H2O(l) + CO2(g) + 2NaNO3(aq)

iii. Cu(NO3)2(aq) + Na2CO3(s)      →  CuCO3(s) + 2NaNO3(aq)

iv.  CuCO3(s) + 2HCl(aq) → CuCl2(aq) + H2O(l) + CO2(g)

v.   CuCl2(aq) +Cu(s) →  2CuCl(s)

Based on the above data, calculate the number of moles of HNO3 that are in   excess.

Also based on the above data , the excess moles of HNO3 used,  and the    moles of

 Cu(NO3)2 produced in the first step, how many grams of sodium  carbonate was

  added     in excess.

 

The answer choices are given in this format.

 

HNO3(excess mols)

Na2CO3(excess grams)

 

 

 

 

 

Group of answer choices

0.0152

4.420

0.0196

1.473

0.0724

2.623

0.0276

1.764

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