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Boron and sulfur form two binary compounds. The first contains 0.2247 g B/1.000 g S, and the second contains 0.1348 g B/1.000 g S. If the formula for the first compound is a multiple of B2S3, then the second is a multiple of: (AW: ? ... B=10.811; S=32.065) A) B2S5 B B257 (© BS3 BS2

Boron and sulfur form two binary compounds. The first contains 0.2247 g B/1.000 g S, and the second contains 0.1348 g B/1.000 g S. If the formula for the first compound is a multiple of B2S3, then the second is a multiple of: (AW: ? ... B=10.811; S=32.065) A) B2S5 B B257 (© BS3 BS2

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter2: Atoms Molecules And Ions
Section: Chapter Questions
Problem 94PS: Elemental sulfur (1.256 g) is combined with fluorine, to give a compound with the formula SFx, a...
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Boron and sulfur form two binary compounds. The first contains 0.2247 g B/1.000 g S, and the second contains 0.1348 g B/1.000 g S. If the formula for the first compound is a multiple of B2S3, then the second is a multiple of: (AW: ? ... B=10.811; S=32.065) A B2S5 B257 (c) BS3 BS2
Transcribed Image Text:Boron and sulfur form two binary compounds. The first contains 0.2247 g B/1.000 g S, and the second contains 0.1348 g B/1.000 g S. If the formula for the first compound is a multiple of B2S3, then the second is a multiple of: (AW: ? ... B=10.811; S=32.065) A B2S5 B257 (c) BS3 BS2
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