please explain The following information is given for cadmium at latm:AHvap (765.00°C) = 889.6 J/gAHfus (321.00°C) = 54.40 J/gT, = 765.00°CTm = 321.00°CSpecific heat solid = 0.2300 J/g °CSpecific heat liquid = 0.2640 J/g °CA 49.50 g sample of liquid cadmium at 382.00°C is poured into a mold and allowed to cool to 23.00°C. How many kJ ofenergy are released in this process?(Report the answer as a positive number.)EnergykJ

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Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter4: Energy And Chemical Reactions

Section4.5: Energy And Enthalpy

Problem 4.6PSP

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The specific heat of an unknown liquid is determined using a sample of molybdenum (Mo) with a mass of 35.12g. The Mo is heated to 99.2OC in boiling water, and then transferred to 52.16g of unknown liquid whose temperature is 23.4OC. The final temperature of the Mo-unknown liquid system is 28.9OC. Calculate the specific heat of the unknown liquid. CMo = 0.251 J•g-1•OC-1
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An engineering student wants to study the heat transfer between a 50 g of a heated block of iron (cFe = 0.449 J/g ⁰C) at 500 ⁰C and 100 g of water (cH2O = 4.184 J/g ⁰C) at 10 ⁰C using a calorimeter. The same student wanted to determine the heat of dissolution for potassium chlorate (KClO3, MW: 122.55 g/mol) in water. He measured 10 grams of KClO3 and dissolved it in a calorimeter containing 250 g of water. The temperature drop was 3.5 K.
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The standard value for the specific heat of aluminum is 0.9 J/g K. Four students gathered and computed their experimental data for the specific heat of aluminum. They did five trials. Julie - 0.90 J/gK; 0.88 J/gK; 0.76 J/gK; 0.88 J/gK; 0.86 J/gK Calix - 0.88 J/gK; 0.89 J/gK; 0.88 J/gK; 0.90 J/gK; 0.90 J/gK Elica - 0.70 J/gK; 0.85 J/gK; 0.94 J/gK; 0.66 J/gK; 0.52 J/gK Leona - 0.52 J/gK; 0.50 J/gK; 0.54 J/gK; 0.50 J/gK; 0.50 J/gK Whose data is precise but not accurate?
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Several ice cubes (ρi = 0.9167 g/cm3) of total volume Vi = 205 cm3 and temperature 273.15 K (0.000 °C) are put into a thermos containing Vt = 680 cm3 of tea at a temperature of 313.15 K, completely filling the thermos. The lid is then put on the thermos to close it. Assume that the density and the specific heat of the tea is the same as it is for fresh water (ρw = 1.00 g/cm3, c = 4186 J/kgK). a. Calculate the equilibrium temperature TE in K of the final mixture of tea and water. b. Calculate the magnitude of the total heat transferred QT in J from the tea to the ice cubes.

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