The following information is given for ethanol, C2H5OH, at 1 atm: boiling point = 78.4 Hvap(78.4 °C) = °C 38.6 kJ/mol melting point = -115 Hfus(-115 °C) = °C 5.02 kJ/mol specific heat liquid = 2.46 J/g°C At a pressure of 1 atm, __kJ of heat are needed to vaporize a 28.0 g sample of liquid ethanol at its normal boiling point of 78.4 °C.

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter9: Liquids And Solids
Section: Chapter Questions
Problem 75QAP: The following data are given for CC14:...
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The following information is given for
ethanol, C2H5OH, at 1 atm:
boiling point = 78.4 Hvap(78.4 °C) =
°C
38.6 kJ/mol
melting point = -115 Hfus(-115 °C) =
°C
5.02 kJ/mol
specific heat liquid =
2.46 J/g°C
At a pressure of 1 atm, __kJ of heat are
needed to vaporize a 28.0 g sample of
liquid ethanol at its normal boiling point of
78.4 °C.
Transcribed Image Text:The following information is given for ethanol, C2H5OH, at 1 atm: boiling point = 78.4 Hvap(78.4 °C) = °C 38.6 kJ/mol melting point = -115 Hfus(-115 °C) = °C 5.02 kJ/mol specific heat liquid = 2.46 J/g°C At a pressure of 1 atm, __kJ of heat are needed to vaporize a 28.0 g sample of liquid ethanol at its normal boiling point of 78.4 °C.
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