i need the answer quickly Q 1J-specimen with the dimensions shown in figure no. 1 below) The following table is the values of true stress - true strain of killed steel0.001 0.010 0.049True Stress (psi) 27024 30839 441000.095 0.14051260 55890True Strain0.1820.2230.336593206208341067-D- 3.3".0.03G = 2.0Figure no. 1 the dimension of killed steel specimenPlot the engineering stress strain graph, pointing each point on the graph, and the determineI Modulus of elasticity2- Yield strength3- Tensile strength4 Fracture stress5- Modulus of resilience

Answered: Image /qna-images/answer/8b662570-42ee-4092-bdf9-45f8a2c96b29.jpg

)The following table is the values of true stress-true strain of killed steel specimen with the dimensions shown in figure no. 1 below True Strain True Stress (psi) 27024 30839 44100 0.001 0.010 0.049 0.095 0.140 0.182 0.223 0.336 51260 55890 59320 62083 41067 D-3.3". 0.03 G=20 Figure no. 1 the dimension of killed steel specimen Plot the engineering stress strain graph, pointing each point on the graph, and the determine I Modulus of elasticity 2- Yield strength 3- Tensile strength 4 Fracture stress 5 Modulus of resilience

)The following table is the values of true stress-true strain of killed steel specimen with the dimensions shown in figure no. 1 below True Strain True Stress (psi) 27024 30839 44100 0.001 0.010 0.049 0.095 0.140 0.182 0.223 0.336 51260 55890 59320 62083 41067 D-3.3". 0.03 G=20 Figure no. 1 the dimension of killed steel specimen Plot the engineering stress strain graph, pointing each point on the graph, and the determine I Modulus of elasticity 2- Yield strength 3- Tensile strength 4 Fracture stress 5 Modulus of resilience

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The data shown in the table below were obtained from a tensile test of high-strength steel. The test specimen had a diameter of 13mm and a gage length of 50mm. At fracture, the elongation between the gage marks was 3.0mm and the minimum diameter was 10.7mm. Plot the conventional stress-strain curve for the steel and determine the propotional limit, modulus of elasticity (i.e the slope of the initial part of the stress-strain curve), yield stress at 0.1% offset, ultimate stress, percent elongation in 50mm, and percent reduction area. TENSILE-TEST DATA Load(kN) Elongation(mm) 5 0.005 10 0.015 30 0.048 50 0.084 60 0.099 64.5 0.109 67.0 0.119 68.0 0.137 69.0 0.160 70.0 0.229 72.0 0.259 76.0 0.330 84.0 0.584 92.0 0.853 100.0 1.288 112.0 2.814 113.0 Fracture
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 150 kN. - Length of the specimen is 24 mm. - The yield strength is 78 kN/mm2. - The percentage of elongation is 42 %. Determine the following iii) Stress under an elastic load of 14 kN, iv) Young's Modulus if the elongation is 1.7 mm at 14 kN and (v) Final diameter if the percentage of reduction in area is 26 %. I wont answer for this three questions only: 1)Final Area of the Specimen at Fracture (in mm) 2)Final Diameter of the Specimen after Fracture (in mm) 3)Initial Cross-sectional Area (in mm2)
The following data were obtained from the tensile test of Aluminum alloy. The initial diameter of testspecimen was 0.505 inch and gauge length was 2.0 inch. Plot the stress strain diagram and determine(a) Proportional Limit (b) Modulus of Elasticity (c) Yield Stress at 0.2% offset (d) Ultimate Stress and(e) Nominal Rupture Stress.
For some metal alloy, a true stress 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 418 MPa (60630 psi) is applied if the original length is 500 mm (19.69in) ? Assume a value of 0.22 for the strain- hardening exponent, n
Annealed low-carbon steel has a flow curve with strength coefficient = 80,000 lb/in2 and strain-hardening exponent = 0.25. A tensile test specimen with gage length = 2.0 in is stretched to a length = 3.5 in. Determine the flow stress and average flow stress that the metal experienced during this deformation. use correct stratgy and correct E 0.55962
The following data (in given figure) were obtained from the tensile test of Aluminum alloy. The initial diameter of test specimen was 0.505 inch and gauge length was 2.0 inch. Plot the stress strain diagram and determine(a) Proportional Limit (b) Modulus of Elasticity (c) Yield Stress at 0.2% offset (d) Ultimate Stress and(e) Nominal Rupture Stress.
A pine wood specimen was prepared with actual dimensions of 50 mm *50 mm * 250 mm and grain parallel to its length. The deformation was measured over a gauge length of 200 mm. The specimen was subjected to compression parallel to the grain to failure. The load–deformation results are as shown in Table P10.25. a. Using a computer spreadsheet program, plot the stress–strainrelationship.b. Calculate the modulus of elasticity.c. What is the failure stress?
Define the term Absolute Maximum Shear Strain?
Annealed low-carbon steel has a flow curve with strength coefficient = 80,000 lb/in2 and strain-hardening exponent = 0.25. A tensile test specimen with gage length = 2.0 in is stretched to a length = 3.5 in. Determine the flow stress and average flow stress that the metal experienced during this deformation.
22) In stress and strain diagram for a perfectly ductile material, the yield strength, and ultimate tensile strength are well defined Select one: True False
1. What are the elastic modulus (E) and the Poisson's ratio () used to indicate? 2. Illustrate the differences between actual stress and engineered stress with strain, and also describe their underlying physical concepts. 3. If the engineering strain is 2% for a specific state of uniaxial stress, what is the real strain? Please solve for all in full detail and step by step
40)A tensile test specimen has a gage length=3.0 inches and a diameter= .75 inches. Yielding occurs at a load of 38000lbs. The corresponding gage length=3.0103 inches (neglect the .0.2% yield point). The maximum load of 54000lbs i9s reached at a gage length =3.453 inches. If the specimen necked down to a diameter=.645 inches, determine the percent reduction in area (Round to the nearest whole %)