The following thermochemical equation is for the reaction of hydrogen chloride(g) with ammonia(g) to form ammonium chloride(s).   HCl(g) + NH3(g) --> NH4Cl(s)              ΔH = -176kJ   How many grams of HCl(g) would have to react to produce 45.2 kJ of energy? _______ grams

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Chapter6: Thermochemisty
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The following thermochemical equation is for the reaction of hydrogen chloride(g) with ammonia(g) to form ammonium chloride(s).

 

HCl(g) + NH3(g) --> NH4Cl(s)              ΔH = -176kJ

 

How many grams of HCl(g) would have to react to produce 45.2 kJ of energy?



_______ grams

 

 

Expert Solution
Step 1

One mole of HCl reacts with one mole of ammonia to form one mole of ammonium chloride. In this process, 176 kJ of energy is released. 

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