The Food Marketing Institute shows that 16% of households spend more than $100 per week on groceries. Assume the population proportion is p = 0.16 and a sample of 800 households will be selected from he population. Use z-table. . Calculate o (P), the standard error of the proportion of households spending more than $100 per week on groceries (to 4 decimals). . What is the probability that the sample proportion will be within +/- 0.02 of the population proportion (to 4 decimals)? What is the probability that the sample proportion will be within +/- 0.02 of the population proportion for a sample of 1,500 households (to 4 decimals)?

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The Food Marketing Institute shows that 16% of households spend more than $100 per week on groceries. Assume the population proportion is p = 0.16 and a sample of 800 households will be selected from
he population. Use z-table.
a. Calculate o (P), the standard error of the proportion of households spending more than $100 per week on groceries (to 4 decimals).
. What is the probability that the sample proportion will be within +/- 0.02 of the population proportion (to 4 decimals)?
. What is the probability that the sample proportion will be within +/- 0.02 of the population proportion for a sample of 1,500 households (to 4 decimals)?
Transcribed Image Text:The Food Marketing Institute shows that 16% of households spend more than $100 per week on groceries. Assume the population proportion is p = 0.16 and a sample of 800 households will be selected from he population. Use z-table. a. Calculate o (P), the standard error of the proportion of households spending more than $100 per week on groceries (to 4 decimals). . What is the probability that the sample proportion will be within +/- 0.02 of the population proportion (to 4 decimals)? . What is the probability that the sample proportion will be within +/- 0.02 of the population proportion for a sample of 1,500 households (to 4 decimals)?
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