Question
Asked Oct 31, 2019
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The force exerted by the wind on the sails of a sailboat is 310 N north. The water exerts a force of 170 N east. If the boat (including its crew) has a mass of 310 kg, what are the magnitude and direction of its acceleration?

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Expert Answer

Step 1

Given situation can be picturized as follows:

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North Fw 310 N Fr West East South F= 170 N Here "Fw" is the force exerted by the wind, "Fe" is the force exerted by the water current.\ Given mass of the crew (m) = 310 Kg

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Step 2

Now the resultant force (Fr) c...

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Fv2 F2 = V3102 1702 = 353.55 N Fr But according to Newton second law: 353.55 1.40 m/s2 F, 3D та — 310 Hence the magnitude of the acceleration is 1.14 m/s2

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Physics

Vectors and Scalars

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