The foreach loop is intended to function with the __________, a temporary, read-only variable. a. variable element b. variable loop c. variable index d. variable iteration
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Types of Loop
Loops are the elements of programming in which a part of code is repeated a particular number of times. Loop executes the series of statements many times till the conditional statement becomes false.
Loops
Any task which is repeated more than one time is called a loop. Basically, loops can be divided into three types as while, do-while and for loop. There are so many programming languages like C, C++, JAVA, PYTHON, and many more where looping statements can be used for repetitive execution.
While Loop
Loop is a feature in the programming language. It helps us to execute a set of instructions regularly. The block of code executes until some conditions provided within that Loop are true.
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- The beginning of the code is given below. #include <stdio.h>#include <string.h> typedef struct{char firstname[20];unsigned height;unsigned weight;} Person; //You can use this functionvoid BufferCleaner(){ while(getchar()!='\n');} void FileCleaner(){FILE *fp; fp = fopen("data/14w_2.txt", "w");fprintf(fp,""); fclose(fp);}using visual studio and the C# please dont copy the previous answered questions because the solution is incorrect In the Chap07 folder of the Student Sample Programs, you will find a file named ChargeAccounts.txt. The file contains a list of a company’s valid charge account numbers. There are a total of 18 charge account numbers in the file, and each one is a 7-digit number, such as 5658845. Create an application that reads the contents of the file into an array or a List. The application should then let the user enter a charge account number. The program should determine whether the number is valid by searching for it in the array or List that contains the valid charge account numbers. If the number is in the array or List, the program should display a message indicating the number is valid. If the number is not in the array or List, the program should display a message indicating the number is invalidThe FKGLF is: 0.39(totalWords/totalSentences) + 11.8(totalSyllables/totalWords) - 15.59Using the FKGLF and your knowledge of how to input and output text files with Java, write an application that will: Take in a text file (anyText.txt), Correct the spelling then save to another file (anyTextCorrected.txt), Calculate the grade level. Outputs. Your solution needs to return: the number of words in the text, the number of spelling errors corrected with the misspelled words listed, the number of sentences in the text, the number of syllables in the text, and the Flesch-Kincaid Grade Level. One assumption you can make is the accuracy of SpellChecker(). You have access to the Java method SpellChecker that takes in a string, assumed to be a word, and returns a correctly spelled word. (Note: If the word returned is different than the word input, then there was a spelling error.) One Constraint: This program requires two classes: GradeLevel and GradeLevelTest. GradeLevel will be the…
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- please can you write a professional comment using the // command for this c++ code thank you #include <iostream>using namespace std; int main (){ char letter; // Place to store input letter int tempIn; // Temperature to be converted int tempOut; // Converted temperature cout << "Input Menu" << endl << endl; cout << "F: Convert from Fahrenheit to Celsius" << endl; cout << "C: Convert from Celsius to Fahrenheit" << endl; cout << "Type a C or an F, then press return." << endl << endl; cout << "Enter your option: "; cin >> letter; // C ,c, f or F { if(letter!='C'||letter!='c'||letter!='F'||letter!='f') cout <<"wrong letter" <<endl; } cout <<"Type an integer number: "; cin >> tempIn; if (letter == 'C') tempOut = (9 * tempIn / 5) + 32; else tempOut = 5 * (tempIn - 32) / 9; cout << endl << endl; cout << "Temperature to…def menu():print("[1] Load Shapes")print("[2]Exit the program")print("[3] Add shapes")print("[4] Save shapes")option = int(input("Enter your option:"))while option != 0:if option > 4:print("Error:please enter a valid number.")break I'd like to add some error handling in here so that if a user types in a letter it prints a message saying "please only enter numbers, no letters"This is a program in C language. Help me debug this program. it has 3 errors. Please upload a screenshot also that it is working thank you./* This porgram uses the gotoxy() function and textcolor() for better screen display */ #include <iostream>#include <conio.h>#include <stdlib.h>using namespace std;main(){ int NoItem,ItemNo,Qty,ctr,Row=5; float UPrice,TAmt,ATendered,Change,APaid=0; char ItemDesc[15],TempChar; system("Color 5");; system("Color 2"); gotoxy(25,1);cout<< "[***] RICHLY SUPERMARKET [***]"; gotoxy(31,2);cout<< "Ayala Avenue, Makati"; gotoxy(6,4);cout<< "Item No. Description Qty. Unit Price Total Amount"; gotoxy(5,22);cout<< "No. of Item(s) Bought => [ ]"; gotoxy(37,22);cout<< "Total Amount to be Paid => "; gotoxy(37,23);cout<< "Amount Customer Tendered => "; gotoxy(37,24);cout<< "Amount of Change => "; gotoxy(31,22);cin>> NoItem;…
- ava problem: Write an application that allows a user to enter the names and birth dates of up to 10 friends. Continue to prompt the user for names and birth-dates until the user enters the sentinel value “ZZZ” for a name or has entered 10 names, whichever comes first. When the user is finished entering names, produce a count of how many names were entered, and then display the names. In a loop, continuously ask the user to type one of the names and display the corresponding birth-date or an error message if the name has not been previously entered. The loop continues until the user enters “ZZZ” for a name.2 In code, create a variable called strName and populate that variable with your name. Your code should then use a for loop to print the letters in strName. Then, print the number of letters in strName (using code to get that number of letters). My name is "LOL" so the output from my code would look like: L O LFix bugs and potential flaws in this code. #include<iostream> int main() {vector<int> coordinates; coordinates.push_back(34);coordinates.push_back(768);coordinates.push_back(516);coordinates.push_back(834); for(auto it = coordinates.begin(); it != coordinates.end(); it++)if(*it == 768)coordinates.erase(it); for(auto& coordinate : coordinates)cout << coordinate << ", ";cout << '\n';return 0;}
