The free energy change for the following reaction at 25 °C, when [Zn2+] = 6.70×10-3 M and [Cr3+] = 1.19 M, is 26.2 kJ: 3Zn2+(6.70×10-3 M) + 2Cr(s)3Zn(s) + 2Cr3+(1.19 M)     ΔG = 26.2 kJ What is the cell potential for the reaction as written under these conditions? Answer:  V Would this reaction be spontaneous in the forward or the reverse direction?

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