The freezing point of water is 0.00°C at 1 atmosphere. How many grams of ammonium chloride (53.50 g/mol), must be dissolved in 211.0 grams of water to reduce the freezing point by 0.500°C ? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula K, (°C/m) K¢(°C/m) Water H2O 0.512 1.86 Ethanol CH;CH,OH 1.22 1.99 Chloroform CHCI3 3.67 Benzene 2.53 5.12 Diethyl ether CH3CH,OCH,CH3 2.02 g ammonium chloride.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter11: Properties Of Solutions
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Problem 111AE: An unknown compound contains only carbon, hydrogen, and oxygen. Combustion analysis of the compound...
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The freezing point of water is 0.00°C at 1 atmosphere.
How many grams of ammonium chloride (53.50 g/mol), must be dissolved in 211.0 grams of water to reduce the freezing point by 0.500°C ? Refer to the table for the necessary boiling or freezing point constant.
Solvent
Formula
Kp (°C/m) Kf (°C/m)
Water
H2O
0.512
1.86
Ethanol
CH3CH,OH
1.22
1.99
Chloroform
CHCI3
3.67
Benzene
CH6
2.53
5.12
Diethyl ether CH3CH2OCH2CH3
2.02
g ammonium chloride.
Transcribed Image Text:The freezing point of water is 0.00°C at 1 atmosphere. How many grams of ammonium chloride (53.50 g/mol), must be dissolved in 211.0 grams of water to reduce the freezing point by 0.500°C ? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Kp (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH,OH 1.22 1.99 Chloroform CHCI3 3.67 Benzene CH6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 g ammonium chloride.
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