The graph in Fig. A shows the velocity of an ambulance vehicle driver plotted as a function of time. How far does the officer go in the first 3 seconds? The first 7 seconds? The first 11 seconds?
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- I have data accrued from a fan could you explain to me the concepts and show me how to calculate the horsepower and work done by the fan that data was composed of below in this table? Time (s) Run #1 Velocity, Blue (m/s) Run #1 0.05 0 0.1 0 0.15 0 0.2 0 0.25 0 0.3 0 0.35 4.04E-04 0.4 4.04E-04 0.45 0 0.5 -4.04E-04 0.55 -4.04E-04 0.6 0 0.65 0 0.7 4.04E-04 0.75 8.08E-04 0.8 4.04E-04 0.85 -4.04E-04 0.9 -8.08E-04 0.95 0 1 8.08E-04 1.05 4.04E-04 1.1 0 1.15 -4.04E-04 1.2 0 1.25 4.04E-04 1.3 0 1.35 0 1.4 -4.04E-04 1.45 0 1.5 4.04E-04 1.55 0 1.6 0 1.65 -4.04E-04 1.7 0 1.75 4.04E-04 1.8 0 1.85 0 1.9 -4.04E-04 1.95 0 2 4.04E-04 2.05 4.04E-04 2.1 4.04E-04 2.15 0 2.2 0 2.25 0 2.3 0 2.35 0 2.4 0 2.45 0 2.5 4.04E-04 2.55 8.08E-04 2.6 8.08E-04 2.65 8.08E-04 2.7 8.08E-04 2.75 8.08E-04 2.8 4.04E-04 2.85 0 2.9 0 2.95 0 3 0 3.05 0 3.1 0 3.15 0 3.2 0 3.25 0 3.3 0 3.35 0…The motion of a jet plane just after landing on a runway is described by the (v -t ) graph. Construct the (s —t ) and (a — t ) graphs for the motion. Here (s =0 ), when (t=0). =15t +ast v () V= ~15t+600 )An airplane starts from rest, travels 5000 ft down a runway, and after uniform acceleration, takes off with a speed of 162 mi/h. It then climbs in a straight line with a uniform acceleration of 3 ft/s^2 until it reaches a constant speed of 220 mi/h. Draw the s–t, v–t, and a–t graphs that describe the motion.
- Dr. Wang was doing donuts (i.e. driving in a circle) in his car over the weekend and used his iPhone to measure the acceleration he experienced (this is a true story). The plot below shows the lateral acceleration recorded by his iPhone. Knowing that he was maintaining a constant speed and that the radius of his donuts was 10 meters, determine how fast he was driving and approximately how many donuts (laps) did he completed in the 6 seconds shown?Graph below represents the force on a 12 kg air mass as it passes through a jet engine. Immediately after entering the engine, the force is 9,039 N, and the force tapers linearly to zero once the air reaches the back of the engine 2.3 m later. If the air enters the engine with velocity 252 m/s, what is its exit velocity? (Please answer to the fourth decimal place - i.e 14.3225)In a physics lab experiment, you release a small steelball at various heights above the ground and measure the ball’s speedjust before it strikes the ground. You plot your data on a graph that hasthe release height (in meters) on the vertical axis and the square of thefinal speed (in m2/s2) on the horizontal axis. In this graph your datapoints lie close to a straight line. (a) Using g = 9.80 m/s2 and ignoringthe effect of air resistance, what is the numerical value of the slope ofthis straight line? (Include the correct units.) The presence of air resistancereduces the magnitude of the downward acceleration, and the effectof air resistance increases as the speed of the object increases. Yourepeat the experiment, but this time with a tennis ball as the object beingdropped. Air resistance now has a noticeable effect on the data. (b) Isthe final speed for a given release height higher than, lower than, or thesame as when you ignored air resistance? (c) Is the graph of the releaseheight…
- The diagram shows a velocity-time graph for a car moving in a straight line. At point P thecar must be ____ and at point Q it must be ______ CHoices: slowing down, slowing down at the right of the origin, at the left of the origin speeding up, slowing down slowing down, speeding up speeding up, speeding up Explain whyA car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground, If Upton free falls for 2.60 seconds. The takeoff speed for this plane will be 65 m/s. Assuming this minimum acceleration, what is the minimum allowed length for the runway? I want typed good format answer.Please don't skip it as advanced physics as it is simple physics problem.The acceleration of a particle traveling along a straight line is a = ¼ s1/2 m/s2 ,where s is in meters. If v = 0 m/s and s = 1 m when t = 0 s, determine the particle’s velocity at s =2 m.NOTE #1 – A sketch of the scenario should be created by you to enhance your work.NOTE #2 – A particle is rather uninspiring, yet they are suitable in learning engineering scienceprinciples. You are welcome to spice up this problem by replacing the particle with a rigid bodyof interest to you. You are welcome to comment on your answer how replacing abstract conceptswith tangible examples influences your learning of dynamics topics
- Applying principles of dynamics, with step by step solutions pls (i give 5 stars) A freighter is moving at a speed of 8 nautical miles per hour. The engines then had to be suddenly stopped. If it takes 10 minutes for the freighter to reduce its speed to 3 knots, determine the distance moved by the ship and its speed at the end of this interval. The deceleration of the ship is propor-tional to the square of its speed such that a = -kV^2.A snowboarder’s velocity is tracked by a pulse-laser velocimeter as she descends the slope. These velocity data are stored and analyzed via an embedded curve fitting procedure to determine a velocity function of v(t) = 1.5t2 + 2t + 2 (t is time in seconds and v is velocity in ft/s). At time equal 0, position (x) is zero. Find her position (e.g., distance traveled), velocity and acceleration formulations and values of each when time equals 15 seconds. Clearly write the formulas before finding respective values at t = 15 seconds!Applying principles of dynamics (with step by steep solutions pls i give 5 stars) The displacement of a particle which moves along the x axis is given by x = (-4 + 3t2)e-0.25t, consider x to be in feet and t in seconds. Plot the displacement, velocity and acceleration for the first 20 seconds of motion and determine, both graphically and by your established equation for acceleration,the time at which acceleration is 0. (If the students find it more comfortable, they may choose to graph using excel or any graphing software, solutions however must be done manually)