Question

Asked Dec 14, 2019

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The graph of y=-4x^2-40x-106 is a parabola that opens in the direction ____. It has vertex _____, y intercept______, and ______ real roots.

a) down, (-5,-6),-106,2

b) down,(-5,-6),-106,0

c) down, (5,-6), -106, 0

d) up, (-5,-6) -106,0

e) none of the above

Step 1

Write the parabola in standard form first. For the comple the square.

Step 2

In this parabola a=-4 is negative so it opens downwards.

It has vertex= (h,k)= (-5,-6)

Step 3

For x=0, y= -106 , so y ...

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