The height, h h , in meters of an object launched straight up after t t seconds can be represented by h ( t ) = − 4.9 t 2 + 30 t h ( t ) = - 4.9 t 2 + 30 t . What is the instantaneous velocity of the object two seconds after it is launched?

The height, h h , in meters of an object launched straight up after t t seconds can be represented by h ( t ) = − 4.9 t 2 + 30 t h ( t ) = - 4.9 t 2 + 30 t . What is the instantaneous velocity of the object two seconds after it is launched?

Algebra for College Students

10th Edition

ISBN:9781285195780

Author:Jerome E. Kaufmann, Karen L. Schwitters

Publisher:Jerome E. Kaufmann, Karen L. Schwitters

Chapter10: Exponential And Logarithmic Functions

Section10.CR: Review Problem Set

Problem 60CR

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