The height h, in feet, of a ball t seconds after being thrown from a height of 6 ft is given by the equation ℎ = −16 2 + 32 + 6. After how many seconds is the ball 18 ft above the ground? Round to the nearest tenth.

Name: The height h, in feet, of a ball t seconds after being thrown from a h
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Description: The height h, in feet, of a ball t seconds after being thrown from a height of 6 ft is given by the equation ℎ = −16 2 + 32 + 6. After how many seconds is the ball 18 ft above the ground? Round to the nearest tenth.

The height of a ball is given by ht=-16t2+32t+6. In order to find the time at which the ball reached…

Answered: The height h, in feet, of a ball t…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter2: Equations And Inequalities

Section: Chapter Questions

Problem 6T

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The height h, in feet, of a ball t seconds after being thrown from a height of 6 ft is given by the equation ℎ = −16 ² + 32 + 6. After how many seconds is the ball 18 ft above the ground? Round to the nearest tenth.

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