The hydroxide ion concentrations will need to be determined to use later in the calculations. The dilution formula is: M₁V₁= = M₂V₂ a. 2.0-mL of 0.10M NaOH and 8.0-mL of water are combined initially. What is the new concentration of the NaOH in the combined solution? (Note the total volume is 10.0- mL) b. 4.0-mL of 0.10M NaOH and 6.0-mL of water are combined initially. What is the new concentration of the NaOH in the combined solution? C. The solution in (a) is combined with 10.0mL of CV. What is the concentration of the NaOH solution? (Note the total volume is now 20.0-mL) d. The solution in (b) is combined with 10.0mL of CV. What is the concentration of the NaOH solution?

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
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Chapter4: Reactions In Aqueous Solution
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Problem 53QAP: The molarity of iodine in solution can be determined by titration with arsenious acid, H3AsO4. The...
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ue Jun 7
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5 +
EN-US My Notes
DOO
O
The hydroxide ion concentrations will need to be determined to use later in the calculations.
The dilution formula is: M₁V₁ = M₂V₂
a. 2.0-mL of 0.10M NaOH and 8.0-mL of water are combined initially. What is the new
concentration of the NaOH in the combined solution? (Note the total volume is 10.0-
mL)
b. 4.0-mL of 0.10M NaOH and 6.0-mL of water are combined initially. What is the new
concentration of the NaOH in the combined solution?
c. The solution in (a) is combined with 10.0mL of CV. What is the concentration of the
NaOH solution? (Note the total volume is now 20.0-mL)
d. The solution in (b) is combined with 10.0mL of CV. What is the concentration of the
NaOH solution?
Suppose a 0.010M concentration of OH produces a k' of 0.0035 /sec and a 0.020M
concentration of OH produces a k' of 0.0071/sec.
Using the equation below, what is the approximate order (value of "x") for the OH ?
a.
k₂
k
[он ],
where k is the true rate constant
k₁ k[OH ]₁
43%
a
●● +
Transcribed Image Text:ue Jun 7 No name 5 + EN-US My Notes DOO O The hydroxide ion concentrations will need to be determined to use later in the calculations. The dilution formula is: M₁V₁ = M₂V₂ a. 2.0-mL of 0.10M NaOH and 8.0-mL of water are combined initially. What is the new concentration of the NaOH in the combined solution? (Note the total volume is 10.0- mL) b. 4.0-mL of 0.10M NaOH and 6.0-mL of water are combined initially. What is the new concentration of the NaOH in the combined solution? c. The solution in (a) is combined with 10.0mL of CV. What is the concentration of the NaOH solution? (Note the total volume is now 20.0-mL) d. The solution in (b) is combined with 10.0mL of CV. What is the concentration of the NaOH solution? Suppose a 0.010M concentration of OH produces a k' of 0.0035 /sec and a 0.020M concentration of OH produces a k' of 0.0071/sec. Using the equation below, what is the approximate order (value of "x") for the OH ? a. k₂ k [он ], where k is the true rate constant k₁ k[OH ]₁ 43% a ●● +
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