The hyperbola with vertices at (0, 3) and (0, – 3) and foci at (0, 5) and (0, – 5) has the equation y2_ x2 = 1 4 9 9 16 A. В. y2 x2 = 1 16 x2 = 1 16 С. O D.

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A: Here is the solution of the given problem. Application of Lagranges Multiplayer.

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A: The given equation of hyperbola is: y2-x2=1

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A: Here we have to find the equation of hyperbola having a center (0,0) with foci at 0,-52 and 0,52 and…

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A: See the details solution in below

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Q: Find an equation of the ellipse with foci at (−3,7)and (−3,−3) and whose major axis has length 20.…

A: The foci of the ellipse is (−3,7)and (−3,−3). The length of the major axis is 20.

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A: We have to find

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A: The given hyperbola equation,        4y2-x2=4

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A: I have appended the formula used in the solution part.

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A: Distance from (x,y) to (-1,0) is:  Distance from (x,y) to (1,0) is:

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A: 16x2+9y2-64x-54y+1=016x2-64x+9y2-54y=-116(x2-4x)+9(y2-6y)=-116(x2-4x+4)+9(y2-6y+9)=-1+64+8116(x-2)2+…

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A: Since you have posted multiple questions, we will solve only first question for you. To getremaining…

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A: Given:    x2 + 2y2 +4x+ 4y +4=0

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A: Given that: (a)        y = 4x2 − 2019x + 83 (b)      x2/42 + y2/62=1 (c).     x2/42 − y2/62=1

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A: We rewrite the equation as: This is an equation of a hyperbola.

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Q: The vertices of hyperbola: 9z? – 4y² = 36, will be Select one: O (0, ±3) O (12,0) O (+3,0) O (0, ±2)

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