The ice cream cone shown below can be approximated as follows: · scoop on top = uniform solid sphere (M1 = 0.027 kg and R1 = 0.03 m) • waffle cone base= cylinder (M2 = 0.038 kg and R2 = 0.01 m), which is uniform and solid also (it's filled with ice cream!) M, R, R2 M, If this entire ice cream cone were to be rotated about the axis shown, Rotational Inertia: a.) What would the the rotational inertia (I) of: Scoop on top: I1 = kg-m2 cone base: I2 = kg-m2 the whole ice cream cone: Itot = kg-m2 b.) Your friend Bob proposes that you can do this calculation more easily. He condenses the entire ice cream cone into a point mass located at the its center of mass, then uses the point mass formula (I=mr2). What would be the distance "r" that he would use, and the rotational inertia that would result from his calculation? m

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Chapter8: Rotational Equilibrium And Rotational Dynamics
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The ice cream cone shown below can be approximated as follows:
Scoop on top
uniform solid sphere (M1 = 0.027 kg and R1
= 0.03 m)
waffle cone base= cylinder (M2 = 0.038 kg and R2
= 0.01 m), which is uniform and solid also (it's filled with ice cream!)
M.
R,
R,
M.
'2
If this entire ice cream cone were to be rotated about the axis shown,
Rotational Inertia:
a.) What would the the rotational inertia (I) of:
scoop on top: I1
kg-m2
cone base: I, :
kg-m2
the whole ice cream cone: Itot
kg-m2
b.) Your friend Bob proposes that you can do this calculation more easily. He condenses the entire ice cream cone into a point mass located at the its
center of mass, then uses the point mass formula (I=mr2).
What would be the distance "r" that he would use, and the rotational inertia that would result from his calculation?
r =
Transcribed Image Text:The ice cream cone shown below can be approximated as follows: Scoop on top uniform solid sphere (M1 = 0.027 kg and R1 = 0.03 m) waffle cone base= cylinder (M2 = 0.038 kg and R2 = 0.01 m), which is uniform and solid also (it's filled with ice cream!) M. R, R, M. '2 If this entire ice cream cone were to be rotated about the axis shown, Rotational Inertia: a.) What would the the rotational inertia (I) of: scoop on top: I1 kg-m2 cone base: I, : kg-m2 the whole ice cream cone: Itot kg-m2 b.) Your friend Bob proposes that you can do this calculation more easily. He condenses the entire ice cream cone into a point mass located at the its center of mass, then uses the point mass formula (I=mr2). What would be the distance "r" that he would use, and the rotational inertia that would result from his calculation? r =
b.) Your friend Bob proposes that you can do this calculation more easily. He condenses the entire ice cream cone into a point mass located at the its
center of mass, then uses the point mass formula (I=mr2).
What would be the distance "r" that he would use, and the rotational inertia that would result from his calculation?
r =
I =
kg-m2
Is Bob's method correct v ---Select---
yes; this is much easier-- thanks Bob!
no; you need to use the object's exact shape in your "I" calculations
Transcribed Image Text:b.) Your friend Bob proposes that you can do this calculation more easily. He condenses the entire ice cream cone into a point mass located at the its center of mass, then uses the point mass formula (I=mr2). What would be the distance "r" that he would use, and the rotational inertia that would result from his calculation? r = I = kg-m2 Is Bob's method correct v ---Select--- yes; this is much easier-- thanks Bob! no; you need to use the object's exact shape in your "I" calculations
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