The image above represents a standing wave in a string with two fixed ends. The standing wave is produced by a vibrator at one end that is vibrating with a frequency of 34.5 Hz. What is The number of nodes? 6 The number of antinodes? 5 Units are required in all entries below. If the length of the string L = 0.900 m, what is the wavelength À of this standing wave? A = 0.36 m Based on the frequency of the vibrator, what is the fundamental frequency of oscillation f, for this string? f = 1.65 Hz What is the wave speed v? v = 2.971 m/s If the total mass hanging on one end of the strir that creates the tension in the string is 0.550 kg, what is the mass density (mass per unit length) of the string? o c444 sla

Elements Of Electromagnetics
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The image above represents a standing wave in a string with two fixed ends. The standing wave is produced by a vibrator at one end that is vibrating
with a frequency of 34.5 Hz.
What is
The number of nodes? 6
The number of antinodes? 5
Units are required in all entries below.
If the length of the string L = 0.900 m, what is the wavelength À of this standing wave?
A = 0.36 m
Based on the frequency of the vibrator, what is the fundamental frequency of oscillation f, for this string?
f1 = 1.65 Hz
What is the wave speed v?
v = 2.971 m/s
If the total mass hanging on one end of the string that creates the tension in the string is 0.550 kg, what is the mass density (mass per unit length) u
of the string?
u = 0.6111 kg/m
The hanging mass is NOT the mass of the string.
Transcribed Image Text:The image above represents a standing wave in a string with two fixed ends. The standing wave is produced by a vibrator at one end that is vibrating with a frequency of 34.5 Hz. What is The number of nodes? 6 The number of antinodes? 5 Units are required in all entries below. If the length of the string L = 0.900 m, what is the wavelength À of this standing wave? A = 0.36 m Based on the frequency of the vibrator, what is the fundamental frequency of oscillation f, for this string? f1 = 1.65 Hz What is the wave speed v? v = 2.971 m/s If the total mass hanging on one end of the string that creates the tension in the string is 0.550 kg, what is the mass density (mass per unit length) u of the string? u = 0.6111 kg/m The hanging mass is NOT the mass of the string.
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