The Intermediate Value Theorem can be used to approximate a root. The following is an example of binary search in computer science. Suppose you want to approximate V8. You know that it is between 2 and 3. If you consider the function f(x) = r? – 8, then note that f(2) < 0 and f(3) > 0. Therefore by the Intermediate Value Theorem, there is a value, 2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 66E
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The Intermediate Value Theorem can be used to approximate a root. The following is an example of binary
search in computer science. Suppose you want to approximate V8. You know that it is between 2 and 3. If
you consider the function f(x) = x2 – 8, then note that f(2) < 0 and f(3) > 0. Therefore by the
Intermediate Value Theorem, there is a value, 2 < c < 3 such that f(c) = 0. Next choose the midpoint
of these two values, 2.5, which is guaranteed to be within 0.5 of the acutal root. f(2.5) will either be less
than 0 or greater than 0. You can use the Intermediate Value Theorem again replacing 2.5 with the previous
endpoint that has the same sign as 2.5. Continuing this process gives a sequence of approximations an with
¤1 = 2.5. How many iterations must you do in order to be within 0.015625 of the root?
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Transcribed Image Text:The Intermediate Value Theorem can be used to approximate a root. The following is an example of binary search in computer science. Suppose you want to approximate V8. You know that it is between 2 and 3. If you consider the function f(x) = x2 – 8, then note that f(2) < 0 and f(3) > 0. Therefore by the Intermediate Value Theorem, there is a value, 2 < c < 3 such that f(c) = 0. Next choose the midpoint of these two values, 2.5, which is guaranteed to be within 0.5 of the acutal root. f(2.5) will either be less than 0 or greater than 0. You can use the Intermediate Value Theorem again replacing 2.5 with the previous endpoint that has the same sign as 2.5. Continuing this process gives a sequence of approximations an with ¤1 = 2.5. How many iterations must you do in order to be within 0.015625 of the root? Submit Question Jump to Answer
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